The h-cobordism theorem is essentially the following result: Let M be a simply connected N-cobordism (with N\geq 6) between V_{0}^{N-1} and V_{1}^{N-1}. Then, M\xrightarrow{\;\cong\;}V_{0}^{N-1}\times [0, 1]. Then, if M is a contractible manifold, one has M\xrightarrow{\;\cong\;}\mathbb{D}^{N}. We can prove this as follows: Let \mathfrak{G} be an embedding of \mathbb{D}^{N} into M and identify the interior \mathrm{Int}(\mathbb{D}), for which M-\mathfrak{G}\left(\mathrm{Int}(\mathbb{D}) \right) is a cobordism \partial M\Longleftrightarrow \mathbb{S}^{N-1}. If we piece these sections back, we would have M from \mathbb{D}^{N-1} and the cobordism M-\mathfrak{G}\left(\mathrm{Int}\left(\mathbb{D} \right) \right)\equiv \mathcal{B}. The following pushout diagram shows this decomposition:
H-cobordisms, Manifolds and Poincare
Here, \mathcal{B} is simply connected (due to homotopy cofiber sequence \mathbb{S}^{N-1}\to \mathcal{B}\to M), and therefore, one can has \mathbb{S}^{N-1}\xrightarrow{\;H\cong\;}\mathcal{B}, where A\xrightarrow{\;H\cong\;}B denotes homotopic equivalence. Now, one can use the h-cobordism result from theorem to identify that \mathcal{B}\xrightarrow{\;\cong\;} \mathbb{S}^{N-1}\times [0, 1]. Gluing \partial \mathbb{D} back, one sees that M\xrightarrow{\;\cong\;}\mathbb{D}^{N-1}, completing the proof. Then, we note the follows: Given a map \mathfrak{G} between \mathbb{S}^{N-1}, one can identify that there exists a homeomorphism \mathfrak{F} between \mathbb{D}^{N}:
Then, the Poincare conjecture can be rewritten into the follows: An N-manifold that is homotopy equivalent to the \mathbb{S}^{N} is also homeomorphic to \mathbb{S}^{N}. As you can guess at this point, the proof of this is somewhat straightforward in terms of the decomposition of the primes \mathbb{D}^{N}_{\pm } and \mathbb{S}^{N-1}_{\pm } under the assumption of the h-cobordism theorem. The proof is as follows. The first diagram shows the decomposition of M=\mathbb{D}_{0}^{N}\sqcup \mathcal{B}\sqcup \mathbb{D}_{1}^{N} by identifying the boundaries of the disks and M-\mathfrak{G}\left(\mathrm{Int}\left(\mathbb{D}_{0}^{N}\sqcup \mathbb{D}_{1}^{N} \right) \right)\equiv \mathcal{B}. Next, using the Alexandrov trick to induce \mathfrak{F} on \mathbb{D}^{N} from \mathfrak{G} homeomorphism induced on \mathbb{S}, we would get the second diagram below:
From the second diagram where we used the Alexandrov trick, we see that there is a homeomorphism between \mathbb{S}^{N} and M by identifying the maps of the N-disks. However, in using the h-cobordism theorem, one has to be sure that the inclusion maps \textit{indeed} have the homotopy equivalence nature. This can be found as a lemma:
Lemma: If M is homotpic to \mathbb{S}^{N} and \mathcal{B} is a cobordism between \mathbb{S}_{0}^{N-1} and \mathbb{S}_{1}^{N-1} as obtained from the subtraction of the N-disk images M-\mathfrak{G}\left(\mathrm{Int}\left(\mathbb{D}_{0}^{N}\sqcup \mathbb{D}_{1}^{N} \right) \right), then \mathbb{S}_{0}^{N-1}\hookrightarrow \mathcal{B} is a homotopy equivalence.
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